Escreva um programa ou função que leva dois inteiros positivos, uma largura e uma altura, e desenha uma arte ASCII houndstooth padrão de grade com essas dimensões usando essa grade de 25 × 26 texto como a célula de base:

.......#.....#####.......
.......##.....#####......
.......###.....#####.....
.......####.....####.....
.......#####.....###.....
.......######.....##.....
.......#######.....#.....
.......########..........
####################.....
.####################....
..####################...
...####################..
....####################.
.....####################
#.....##############.####
##.....#############..###
###....#############...##
####...#############....#
#####..#############.....
.#####.#############.....
..##################.....
........#####............
.........#####...........
..........#####..........
...........#####.........
............#####........

Portanto, se a entrada fosse 2,1a saída, seria:

.......#.....#####..............#.....#####.......
.......##.....#####.............##.....#####......
.......###.....#####............###.....#####.....
.......####.....####............####.....####.....
.......#####.....###............#####.....###.....
.......######.....##............######.....##.....
.......#######.....#............#######.....#.....
.......########.................########..........
####################.....####################.....
.####################.....####################....
..####################.....####################...
...####################.....####################..
....####################.....####################.
.....####################.....####################
#.....##############.#####.....##############.####
##.....#############..#####.....#############..###
###....#############...#####....#############...##
####...#############....#####...#############....#
#####..#############.....#####..#############.....
.#####.#############......#####.#############.....
..##################.......##################.....
........#####....................#####............
.........#####....................#####...........
..........#####....................#####..........
...........#####....................#####.........
............#####....................#####........

E se a entrada fosse 5,4a saída seria:

.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........
.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........
.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........
.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........

• O argumento da largura deve vir primeiro. Qualquer formato de entrada razoável (por exemplo w,h, w h, (w, h)) é bom.
• Imprima ou retorne o resultado com uma nova linha à direita opcional.
• Você pode usar dois caracteres ASCII imprimíveis distintos no lugar de .e #.
• Você pode converter a célula base vertical ou horizontalmente, como se tivesse condições de contorno periódicas . Portanto, o canto superior esquerdo da saída não será necessariamente um retângulo 7 × 8 de .'s. ( Nova regra! )

O código mais curto em bytes vence.

Como bônus, gere uma imagem em que cada .um é um pixel de uma cor e cada #um é um pixel de outra cor.

Pitão, 61 60 55 49 bytes

j*vwmjk*Qd++Rm012Jmms}k++Rhd5U-d4T=T13+Lm1T_mP_dJ

Experimente online: Demonstração

editar 1: Combine as duas instruções que geram a banda e o triângulo (veja abaixo)

editar 2: não viu que podemos usar qualquer símbolo. Salvo 5 bytes editar

edit 3: @ Calvin'sHobbies permitido traduzir a imagem base. Como minha abordagem foi baseada nessa idéia, isso ajudou bastante. -6 bytes

E para o bônus do Cookie :

.w*vw*RQ++Rm012Jmm*K255}k++Rhd5U-d4T=T13+LmKT_mP_dJ

Isso tem apenas 2 bytes mais (51 bytes) e gera o arquivo o.png. Para a entrada 5\n4, gera a seguinte imagem:

Explicação:

O padrão Houndstooth parece realmente bastante irregular. Mas se trouxemos as 7 colunas da esquerda para a direita e as 5 principais linhas para o botão, obtemos um padrão muito melhor:

.#####...................
..#####..................
...#####.................
....#####................
.....#####...............
#.....#####..............
##.....#####.............
###.....#####............
####.....####............
#####.....###............
######.....##............
#######.....#............
########.................
#############.....#######
##############.....######
###############.....#####
################.....####
#################.....###
##################.....##
#############.#####.....#
#############..#####.....
#############...#####....
#############....#####...
#############.....#####..
#############......#####.
#############.......#####

Primeiro, produzo o bloco 13x13 superior esquerdo:

.#####.......
..#####......
...#####.....
....#####....
.....#####...
#.....#####..
##.....#####.
###.....#####
####.....####
#####.....###
######.....##
#######.....#
########.....

Existem 2 desigualdades simples, que descrevem as duas #áreas. A banda pode ser descrita por y + 1 <= x <= y + 5e o triângulo pode ser descrito por x <= y - 5. Eu combinei essas duas condições:

Jmms}k++Rhd5U-d4T=T13
                 =T13   T = 13
 m               T      map each d of [0, 1, ..., 12] to: 
                           the list produced by
  m             T          map each k of [0, 1, ..., 12] to:
       +Rhd5                  the list [d+1, d+2, ..., d+5]
      +                       extended by 
            U-d4              the list [0, 1, ..., d - 5]
    }k                        test if k is in the list
   s                          and convert the boolean result to 1 or 0
J                       assign this 13x13 block to J

Em seguida, +Rm012adiciona 12 zeros no final de cada linha para obter o bloco superior de 25x13.

O bloco inferior de 25x13 agora é realmente simples:

+Lm1T_mP_dJ
      m   J    map each row d of J to:
       P_d        reverse the row and pop the last element
     _         reverse the order the rows
+Lm1T          add T ones at the beginning of each row. 

Tudo o que resta agora é repetir o padrão e imprimi-lo

j*vwmjk*Qd+upperlower   implicit: Q = first input number
          +upperlower   combine the two blocks to a 25x26 block
    m                   map each row d to:
       *Qd                 repeat d Q times
     jk                    and join to a string
 *vw                    read another number from input and repeat
j                       join by newlines and print

A diferença para o código de bônus do Cookie :

• 255 ao invés de 1
• em vez de mjk*Qdusar *RQ, já que não quero uma string
• .w salva esse array 2D em arquivo (o converte em png implicitamente)

CJam, 106 73 71 bytes

0000000: 71 7e 22 04 94 51 af 40 6e 73 b2 68 3a e1 7e 13 f2 a1  q~"[email protected]:.~...
0000012: 3e 1d de f5 64 9c 6b 0f 27 4c 36 d7 81 3d 30 35 56 f8  >...d.k.'L6..=05V.
0000024: cd e8 cd 7c dc 90 31 59 40 8b 8c 22 32 35 36 62 32 32  ...|..1Y@.."256b22
0000036: 62 41 73 33 39 2a 2e 2a 73 32 35 2f 2a 66 2a 4e 2a     bAs39*.*s25/*f*N*

Imprime 1e em 0vez de .e #. Experimente online no intérprete CJam .

Como funciona

q~      e# Read and evaluate all input. This pushes W and H.
"…"     e# Push an encoding of run lengths of the characters in the output.
256b22b e# Convert from base 256 to base 22.
As39*   e# Push "10" and repeat it 39 times.
.*      e# Vectorized character repetition; multiply each base 22 digit (run
        e# length) by the corresponding character of "10…10".
s25/    e# Flatten and split into chunks of length 25.
*       e# Repeat the resulting array of rows H times.
f*      e# Repeat each row W times.
N*      e# Join the rows, separating by linefeeds.

Bônus de cookie

0000000: 27 50 6f 31 70 71 7e 5d 5f 5b 32 35 5f 29 5d 2e 2a 5c  'Po1pq~]_[25_)].*\
0000012: 7e 22 04 94 51 af 40 6e 73 b2 68 3a e1 7e 13 f2 a1 3e  ~"[email protected]:.~...>
0000024: 1d de f5 64 9c 6b 0f 27 4c 36 d7 81 3d 30 35 56 f8 cd  ...d.k.'L6..=05V..
0000036: e8 cd 7c dc 90 31 59 40 8b 8c 22 32 35 36 62 32 32 62  ..|..1Y@.."256b22b
0000048: 41 73 33 39 2a 2e 2a 73 32 35 2f 2a 66 2a 73 2b 4e 2a  As39*.*s25/*f*s+N*

imprime um BitMap portátil em vez de ASCII art.

Abaixo está a saída para entrada 24 13, convertida em PNG:

Befunge-93 , 2120 1967 bytes

Aqui estão alguns exemplos de alta qualidade, com manipulação de exceção para depuração!

&&00p10pv
v       <
    >94+2*20p        v
>00g|   >                v
    @                >10g>0020gv-1:<
                               >:0`|
                     ,       v    $<
                     +        >v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v
 v_$1-:#^_$20g1-20p55^       >|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>"!DAB"....@
 ,:
 >^".......#.....#####......."                                                    <
  ^".......##.....#####......"                                                  <
  ^".......###.....#####....."                                                <
  ^".......####.....####....."                                              <
  ^".......#####.....###....."                                            <
  ^".......######.....##....."                                          <
  ^".......#######.....#....."                                        <
  ^".......########.........."                                      <
  ^"####################....."                                    <
  ^".####################...."                                  <
  ^"..####################..."                                <
  ^"...####################.."                              <
  ^"....####################."                            <
  ^".....####################"                          <
  ^"#.....##############.####"                        <
  ^"##.....#############..###"                      <
  ^"###....#############...##"                    <
  ^"####...#############....#"                  <
  ^"#####..#############....."                <
  ^".#####.#############....."              <
  ^"..##################....."            <
  ^"........#####............"          <
  ^".........#####..........."        <
  ^"..........#####.........."      <
  ^"...........#####........."    <
  ^"............#####........"  <
^                     p00-1g00<

(Obviamente, isso ainda é muito jogável. Eu só queria obter uma resposta aqui por enquanto)

Então, isso é composto de partes diferentes.

&&00p10p

Este é apenas o inicializador, pega os valores e os armazena

    >94+2*20p
>00g|      > 
    @  

Esta seção redefine a contagem de linhas, para que possamos imprimir outras fotos (de largura) lado a lado. 94+2*está calculando 26, o número de linhas. Além disso, se a altura for zero, o programa será encerrado.

>10g

Isso fica com a largura da pilha, para que possamos saber quantas imprimir

0020gv-1:<
     >:0`|
         $

Isso adiciona dois valores fictícios à pilha para dizer quando terminamos uma operação, bem como em que linha (n) estamos. Isso adiciona n valores à pilha

>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v
|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>"!DAB"....@

                                                    <
                                                  <
                                                <
                                              <
                                            <
                                          <
                                        <
                                      <
                                    <
                                  <
                                <
                              <
                            <
                          <
                        <
                      <
                    <
                  <
                <
              <
            <
          <
        <
      <
    <
  <
<

Esta é uma seção de controle que irá para a linha (26-n). Esta é a maneira mais fácil de descobrir como fazê-lo.

".......#.....#####......."
".......##.....#####......"
".......###.....#####....."
".......####.....####....."
".......#####.....###....."
".......######.....##....."
".......#######.....#....."
".......########.........."
"####################....."
".####################...."
"..####################..."
"...####################.."
"....####################."
".....####################"
"#.....##############.####"
"##.....#############..###"
"###....#############...##"
"####...#############....#"
"#####..#############....."
".#####.#############....."
"..##################....."
"........#####............"
".........#####..........."
"..........#####.........."
"...........#####........."
"............#####........"

Obviamente, isso é lido e exibirá qualquer linha lida na pilha de trás para frente. Isso significa que, quando o abrirmos, ele será impresso corretamente.

v_
,:
>^

Isso será impresso até que a pilha atinja um 0, que deixamos anteriormente.

1-:#^_

Isso retira 1 do número da linha específica a ser impressa e verifica se é zero ou não. Se for diferente de zero, voltaremos ao quarto bloco de código.

          ,
          +
20g1-20p55^

Isso subtrai 1 da linha (n), imprime uma nova linha e volta ao bloco 3

p00-1g00

Uma vez impressas todas as linhas, isso subtrai uma da altura inicial e volta para o bloco 2.

Todo o restante do código é fluxo de controle ou gerenciamento de pilha. Escrever esse mas mais do que eu pensava, mas estou satisfeito com a aparência. É muito mais jogável e provavelmente continuará sendo um projeto por mais um dia.

2120 -> 1967 : aparadas algumas linhas com muitos espaços desperdiçados

Perl, 243

(Um byte foi adicionado para que o -ncomutador busque entrada de stdin.)

($w,$h)=split;for(1..$h){print((sprintf("%025b",hex)x$w).$/)foreach qw(20f80 307c0 383e0 3c1e0 3e0e0 3f060 3f820 3fc00 1ffffe0 fffff0 7ffff8 3ffffc 1ffffe fffff 107ffef 183ffe7 1c3ffe3 1e3ffe1 1f3ffe0 fbffe0 7fffe0 1f000 f800 7c00 3e00 1f00)}

Isso é bastante simples - basta converter uma matriz de 26 números hexadecimais em binários e imprimi-los o número necessário de vezes.

Exemplo:

Entrada:

3 2

Saída:

000000010000011111000000000000001000001111100000000000000100000111110000000
000000011000001111100000000000001100000111110000000000000110000011111000000
000000011100000111110000000000001110000011111000000000000111000001111100000
000000011110000011110000000000001111000001111000000000000111100000111100000
000000011111000001110000000000001111100000111000000000000111110000011100000
000000011111100000110000000000001111110000011000000000000111111000001100000
000000011111110000010000000000001111111000001000000000000111111100000100000
000000011111111000000000000000001111111100000000000000000111111110000000000
111111111111111111110000011111111111111111111000001111111111111111111100000
011111111111111111111000001111111111111111111100000111111111111111111110000
001111111111111111111100000111111111111111111110000011111111111111111111000
000111111111111111111110000011111111111111111111000001111111111111111111100
000011111111111111111111000001111111111111111111100000111111111111111111110
000001111111111111111111100000111111111111111111110000011111111111111111111
100000111111111111110111110000011111111111111011111000001111111111111101111
110000011111111111110011111000001111111111111001111100000111111111111100111
111000011111111111110001111100001111111111111000111110000111111111111100011
111100011111111111110000111110001111111111111000011111000111111111111100001
111110011111111111110000011111001111111111111000001111100111111111111100000
011111011111111111110000001111101111111111111000000111110111111111111100000
001111111111111111110000000111111111111111111000000011111111111111111100000
000000001111100000000000000000000111110000000000000000000011111000000000000
000000000111110000000000000000000011111000000000000000000001111100000000000
000000000011111000000000000000000001111100000000000000000000111110000000000
000000000001111100000000000000000000111110000000000000000000011111000000000
000000000000111110000000000000000000011111000000000000000000001111100000000
000000010000011111000000000000001000001111100000000000000100000111110000000
000000011000001111100000000000001100000111110000000000000110000011111000000
000000011100000111110000000000001110000011111000000000000111000001111100000
000000011110000011110000000000001111000001111000000000000111100000111100000
000000011111000001110000000000001111100000111000000000000111110000011100000
000000011111100000110000000000001111110000011000000000000111111000001100000
000000011111110000010000000000001111111000001000000000000111111100000100000
000000011111111000000000000000001111111100000000000000000111111110000000000
111111111111111111110000011111111111111111111000001111111111111111111100000
011111111111111111111000001111111111111111111100000111111111111111111110000
001111111111111111111100000111111111111111111110000011111111111111111111000
000111111111111111111110000011111111111111111111000001111111111111111111100
000011111111111111111111000001111111111111111111100000111111111111111111110
000001111111111111111111100000111111111111111111110000011111111111111111111
100000111111111111110111110000011111111111111011111000001111111111111101111
110000011111111111110011111000001111111111111001111100000111111111111100111
111000011111111111110001111100001111111111111000111110000111111111111100011
111100011111111111110000111110001111111111111000011111000111111111111100001
111110011111111111110000011111001111111111111000001111100111111111111100000
011111011111111111110000001111101111111111111000000111110111111111111100000
001111111111111111110000000111111111111111111000000011111111111111111100000
000000001111100000000000000000000111110000000000000000000011111000000000000
000000000111110000000000000000000011111000000000000000000001111100000000000
000000000011111000000000000000000001111100000000000000000000111110000000000
000000000001111100000000000000000000111110000000000000000000011111000000000
000000000000111110000000000000000000011111000000000000000000001111100000000

Rev 1, C, 118 115 bytes

i,x,y;f(w,h){for(i=26*h*(w*=25);i--;i%w||puts(""))x=i%25,y=i/w%26,putchar(((y>x^y>x+5^x>y+4)&y/13==x/13^y/13)+34);}

9 bytes salvos devido a nova regra que permite a conversão da célula. 3 bytes salvos pelo uso de w*=25. O restante da postagem permanece inalterado.

Rev 0, C, 127 bytes

i,x,y;f(w,h){for(i=650*w*h;i--;i%(25*w)||puts(""))x=(i+20)%25,y=(i/25/w+8)%26,putchar(((y>x^y>x+5^x>y+4)&y/13==x/13^y/13)+34);}

Isso passa pelos caracteres, imprimindo-os um por um. i%(25*w)||puts("")insere uma nova linha no final de cada linha.

Minha maneira de visualizar o design é semelhante à de Jakube, mas trago as 8 linhas superiores para a parte inferior e as 5 colunas da direita para a esquerda para obter a seguinte visualização. No programa, essa etapa é "revertida" por +20e +8nas expressões para x e y.

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Além da "inversão de cores", pode parecer muito semelhante, mas há uma diferença importante: as listras diagonais coincidem. (observe que o design original não possui simetria diagonal, pois mede 25x26.)

A expressão ((y>x^y>x+5^x>y+4)^y/13)+34produz o seguinte, onde os vários operadores de comparação produzem as listras, ^y/13produz o "deslocamento da cor" até a metade e +34pega o número resultante 0,1e o eleva para o intervalo ASCII 34,35.

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O termo é &y/13==x/13avaliado como false = 0 nos quartos superior direito e inferior esquerdo, produzindo a parte quadrada do padrão, como mostrado anteriormente. Observe que, como o programa reduz a contagem, a origem x = y = 0 está no canto inferior direito. Isso é útil, pois o quadrado de #13 caracteres de largura, enquanto o quadrado de "apenas 12 caracteres de largura.

Befunge -93, 968 bytes

Sim está certo! Uma resposta concorrente da Befunge!

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Explicação amanhã, cama agora. No entanto, direi que faço coisas inteligentes movendo algumas setas de redirecionamento e também uso a propriedade wrap-around bastante. Teste-o neste intérprete online .