Acesse o último elemento no vetor em C
vector<int> v;
cout << v[v.size() - 1];
cout << *(v.end() - 1);
cout << *v.rbegin();
// all three of them work
Zany Zebra
vector<int> v;
cout << v[v.size() - 1];
cout << *(v.end() - 1);
cout << *v.rbegin();
// all three of them workvector<int> vec;
vec.push_back(0);
vec.push_back(1);
int last_element = vec.back();
int also_last_element = vec[vec.size() - 1];
arr2.rbegin()[1] // rbegin() is reverse order starting at 0 for last element, 1 for second-lastint var = vec.back().c;#include<iostream>
/*To get the last element of the array we first get the size
of the array by using sizeof(). Unfortunately, this gives
us the size of the array in bytes. To fix this, we divide
the size (in bytes) by the size of the data type in the array.
In our case, this would be int, so we divide sizeof(array)
by sizeof(int). Since arrays start from 0 and not 1 we
subtract one to get the last element.
-yegor*/
int array[5] = { 1, 2, 3, 4, 5 };
printf("Last Element of Array: %d", array[(sizeof(array)/sizeof(int))-1]);