“conversor python para javascript online” Respostas de código

conversor python para javascript online

 for i in arr:
    if i==num:
      num=num*2
  return num
Plain Peacock

conversor python para javascript online

pen = turtle.Turtle()
pen.color("yellow")
pen.width(3)
pen.hideturtle()
pen.penup()
pen.goto(-30, 60)
pen.pendown()
pen.fd(60)
pen.rt(90)
pen.fd(120)
pen.rt(90)
pen.fd(60)
pen.rt(90)
pen.fd(120)
Expensive Elk

conversor python para javascript online

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))
for i in range(1, n+1):
    print('*' * i)
Different Dolphin

conversor python para javascript online

x = 3
print(x)
Misty Magpie

conversor python para javascript online

def StringPeriods (s):

for i in range (int (len (s)/2), 0,-1):

a = s[i] count = 2

b = "

while len (b)

b = a * count

if b == s:

return a

len(s):

count += 1

return -1
Delightful Dove

conversor python para javascript online

class Solution:
    def solve(self, s):
        x = ""
        for i in s:
            if i >= 'a' and i <= 'z':
                x += i
        i, j = 0, len(x) - 1
        while i <= j:
            if x[i] != x[j]:
                return False
            i += 1
            j -= 1
        return True
Homeless Horse

conversor python para javascript online

pen = turtle.Turtle()
pen.color("yellow")
pen.width(3)
pen.hideturtle()
pen.penup()
pen.goto(-30, 60)
pen.pendown()
pen.fd(60)
pen.rt(90)
pen.fd(120)
pen.rt(90)
pen.fd(60)
pen.rt(90)
pen.fd(120)
Expensive Elk

conversor python para javascript online

pen = turtle.Turtle()
pen.color("yellow")
pen.width(3)
pen.hideturtle()
pen.penup()
pen.goto(-30, 60)
pen.pendown()
pen.fd(60)
pen.rt(90)
pen.fd(120)
pen.rt(90)
pen.fd(60)
pen.rt(90)
pen.fd(120)
Expensive Elk

conversor python para javascript online

n = 0
while n <= 0:
    n = int(input("Enter the number of lines: "))
for i in range(1, n+1):
    for j in range(1, i+1):
        print('*', end='')
    print()
Different Dolphin

conversor python para javascript online

if g == 0:
        return [1] * len(originCities)
    if g >= n:
        return [0] * len(originCities)
    components = {i: i for i in range(g + 1, n + 1)}
    for candidate in range(g + 1, n + 1):
        current = [t * candidate for t in range(1, n // candidate + 1)]
        current_components = [components[e] for e in current]
        minone = min(current_components)
        for curr in current:
            components[curr] = minone
    res = []
    for k in range(len(originCities)):
        origin, destination = originCities[k], destinationCities[k]
        if origin > g and destination > g and components[origin] == components[destination]:
            res.append(1)
        else:
            res.append(0)
    return res
Stormy Seahorse

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