“Javascript Time atrás Função” Respostas de código

Javascript Time atrás Função

function timeSince(date) {

  var seconds = Math.floor((new Date() - date) / 1000);

  var interval = seconds / 31536000;

  if (interval > 1) {
    return Math.floor(interval) + " years";
  }
  interval = seconds / 2592000;
  if (interval > 1) {
    return Math.floor(interval) + " months";
  }
  interval = seconds / 86400;
  if (interval > 1) {
    return Math.floor(interval) + " days";
  }
  interval = seconds / 3600;
  if (interval > 1) {
    return Math.floor(interval) + " hours";
  }
  interval = seconds / 60;
  if (interval > 1) {
    return Math.floor(interval) + " minutes";
  }
  return Math.floor(seconds) + " seconds";
}
var aDay = 24*60*60*1000;

console.log(timeSince(new Date(Date.now()-aDay)));
console.log(timeSince(new Date(Date.now()-aDay*2)));
Poor Pollan

Como mostrar 1 dia atrás em JavaScript

function timeSince(date) {

  var seconds = Math.floor((new Date() - date) / 1000);

  var interval = seconds / 31536000;

  if (interval > 1) {
    return Math.floor(interval) + " years";
  }
  interval = seconds / 2592000;
  if (interval > 1) {
    return Math.floor(interval) + " months";
  }
  interval = seconds / 86400;
  if (interval > 1) {
    return Math.floor(interval) + " days";
  }
  interval = seconds / 3600;
  if (interval > 1) {
    return Math.floor(interval) + " hours";
  }
  interval = seconds / 60;
  if (interval > 1) {
    return Math.floor(interval) + " minutes";
  }
  return Math.floor(seconds) + " seconds";
}
var aDay = 24*60*60*1000;
console.log(timeSince(new Date(Date.now()-aDay)));
console.log(timeSince(new Date(Date.now()-aDay*2)));
Weary Wombat

TypeScript/JavaScript Time atrás do DateTime

/**
 * A function that converts date object to human readable time ago
 * @param {Date} date
 * @returns {string}
 * @author [YogPanjarale](https://github.com/YogPanjarale)
 */
 export function dateToTimeAgo(date: Date): string {
	const now = new Date(Date.now());
	const difftime = now.getTime() - date.getTime();
	const diffDate = new Date(difftime - 5.5 * 60 * 60 * 1000);
	const [sec, min, hr, day, month] = [
		diffDate.getSeconds(),
		diffDate.getMinutes(),
		diffDate.getHours(),
		diffDate.getDate() - 1,
		diffDate.getMonth(),
	];
	const f = (property, end) =>{
		// console.log(property,end)
		return`${property} ${end}${property > 1 ? "s" : ""} ago`;
	}
	// console.log(diffDate.toLocaleString());
	return month >= 1
		? f(month, "month")
		: day >= 1
		? f(day, "day")
		: hr >= 1
		? f(hr, "hr")
		: min >= 1
		? f(min, "min")
		: day >= 1
		? f(sec, "sec")
		: "";


	throw new Error("Date To time ago not implmented");
}
Yog

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