soma de todos os múltiplos de 3 e 5 abaixo de 100
c = list(range(1,100))
total = 0
for i in (c):
if i % 3 == 0 or i % 5 == 0:
total += i
print (total)
Dizzy Duck
c = list(range(1,100))
total = 0
for i in (c):
if i % 3 == 0 or i % 5 == 0:
total += i
print (total)nums = [3, 5]
result = 0
for i in range(0,1000):
if i%3 == 0 or i%5 == 0:
result += i
print(result)
total_sum = 0
for i in range(1000):
if (i%3 == 0 or i%5 == 0):
total_sum = total_sum+i
print total_sumtotal = []
for num in range(0,1001):
if (num % 3 == 0) or (num % 5 == 0):
total.append(num)
print(sum(total))total = 0
for i in range(1, 100):
if i % 3 == 0:
total = total + i
print(total)
total1 = 0
for i in range(1, 100):
if i % 5 == 0:
total1 = total1 + i
print(total1)
const findSum = n => {
let countArr = []
for(let i = 0; i <= n; i++) if(i % 3 === 0 || i % 5 === 0) countArr.push(i)
return countArr.reduce((acc , curr) => acc + curr)
}
console.log(findSum(5))