Classificar lista de dicionários por Key Python
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
Stupid Stork
newlist = sorted(list_to_be_sorted, key=lambda k: k['name']) unsorted_list = [{"key1":5, "key2":2}, {"key1":5, "key2":1}]
sorted_list = sorted(unsorted_list, key=lambda k: k["key2"])channels = {
'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'},
'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'},
'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'},
'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'},
'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'},
'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'},
'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
}
channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
for key,value in channels.items():
print(key, ':', value)def sort_dict(dictionary, rev = True):
l = list(dictionary.items())
l.sort(reverse = rev)
a = [item[1] for item in l]
z = ''
for x in a:
z = z + str(x)
return(z)