“Sobrecarga da função Python” Respostas de código

Sobrecarga da função Python

registry = {}


class MultiMethod(object):
    def __init__(self, name):
        self.name = name
        self.typemap = {}

    def __call__(self, *args):
        types = tuple(arg.__class__ for arg in args)  # a generator expression!
        function = self.typemap.get(types)
        if function is None:
            raise TypeError("no match")
        return function(*args)

    def register(self, types, function):
        if types in self.typemap:
            raise TypeError("duplicate registration")
        self.typemap[types] = function


def multimethod(*types):
    def register(function):
        name = function.__name__
        mm = registry.get(name)
        if mm is None:
            mm = registry[name] = MultiMethod(name)
        mm.register(types, function)
        return mm

    return register

###### usage ######
from multimethods import multimethod

# 'overload' makes more sense in this case
overload = multimethod


@overload(str, int)
def do_smth(a, b):
    print(a + b)


@overload(str)
def do_smth(a):
    print(a)